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  4. A face-centred cubic element (atomic mass 60) has a cell edge of 400 pm. What'is its density?

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Q. A face-centred cubic element (atomic mass 60) has a cell edge of 400 pm. What'is its density?

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Solution:

$\rho = \frac{Z \times M}{a^{3} \times N_{0}} $
$ = \frac{40 \times60 \text{g} \text{mol}^{-1}}{\left(400 \times10^{-10} \text{cm} \right)^{3} \times6.02 \times10^{23} \text{mol}^{-1}} $
$ = 6.2 \text{g} \text{cm}^{-3} $