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  4. A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward followed again by 5 steps forward and 3 steps backward and so on. Each step is one metre long and takes one second. There is a pit on the road 11 metre away from the starting point. The drunkard will fall into the pit after

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Q. A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward followed again by 5 steps forward and 3 steps backward and so on. Each step is one metre long and takes one second. There is a pit on the road 11 metre away from the starting point. The drunkard will fall into the pit after

Motion in a Straight Line

Solution:

Displacement in first eight steps $=5 m -3 m =2 m$ Time taken for first eight steps $=8 s$
Time taken by drunkard to cover first six metres of journey
$=\frac{8}{2} \times 6=24 s$
If the drunkard takes 5 steps more, he will fall into the pit so the time taken by the drunkard to cover last five steps $=5 s$
Total time taken $=24 s +5 s =29 \,s$