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Q. A disk with moment of inertia $I_{1}$ rotates about a frictionless, vertical axle with angular speed $\omega_{i}$ A second disk, this one having moment of inertia $I_{2}$ and initially not rotating, drops onto the first disk (Fig.). Because of friction between the surfaces, the two eventually reach the same angular speed $\omega_{f}$ The value of $\omega_{f}$ isPhysics Question Image

System of Particles and Rotational Motion

Solution:

From conservation of angular momentum for the isolated system of two disks:
$\left(I_{1}+I_{2}\right) \omega_{f}=I_{1} \omega_{i} \text { or } \omega_{f .}=\frac{I_{1}}{I_{1}+I_{2}} \omega_{i}$