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  4. A disc spinning at the rate 27.5 rad s is slowed at the rate 10 rad s-2. The time after which it will come to rest is

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Q. A disc spinning at the rate $27.5$ rad s is slowed at the rate $10\, rad \,s^{-2}$. The time after which it will come to rest is

KEAMKEAM 2020

Solution:

$t=\frac{\omega}{\alpha}=\frac{27.5}{10}=2.75 \,s$