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Q.
A disc of mass $M$ and radius $R$ is rotating about one of its diameter. The value of radius of gyration for the disc is
System of Particles and Rotational Motion
Solution:
$I_{\text{ disc} }$ about the axis along its diameter
$=\frac{M R^{2}}{4}$ ...(i)
Using radius of gyration, $I=M k^{2}$ ...(ii)
Comparing Eqs. (i) and (ii), we get $k=\frac{R}{2}$.
