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  4. A disc is rolling on an inclined plane without slipping then what fraction of its total energy will be in form of rotational kinetic energy :-

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Q. A disc is rolling on an inclined plane without slipping then what fraction of its total energy will be in form of rotational kinetic energy :-

System of Particles and Rotational Motion

Solution:

Fraction $=\frac{K_{\text {Rotation }}}{K_{\text {Total }}}=\frac{\frac{K^{2}}{R^{2}}}{1+\frac{K^{2}}{R^{2}}}$
For disc, $\frac{K^{2}}{R^{2}}=\frac{1}{2}$
so, fraction $=\frac{\frac{1}{2}}{1+\frac{1}{2}}$
$=1: 3$