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  4. A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in figure. At any instant, for the lower most point of the disc -

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Q. A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in figure. At any instant, for the lower most point of the disc -Physics Question Image

BITSATBITSAT 2013

Solution:

$v _{ A }=0$ (due to pure rolling)
Angular acceleration (for A), a
$=R w^{2}=R \frac{v^{2}}{R^{2}}$
$\Rightarrow a=\frac{v^{2}}{R}$

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