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Q. A direct current deposits $54 \,g$ of silver (atomic mass $=108$ ) during the electrolysis. The same quantity of electricity would deposit aluminium (atomic mass $=27$ ) from aluminium chloride in molten state equal to

Electrochemistry

Solution:

$\frac{w_{1}}{w_{2}}=\frac{E_{1}}{E_{2}}$
$ \Rightarrow \frac{54}{w_{2}}=\frac{\frac{108}{1}}{\frac{27}{3}}$
$E_{1}=\frac{M}{n \text {-factor }}=\frac{108}{1}$
for $Ag ^{+}, E_{2}=\frac{27}{3}$ for $Al ^{3+}$
$\therefore w_{2}=\frac{54 \times 9}{108}=4.5 \,g$