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  4. A dielectric slab of dielectric constant K is placed between the plates of a parallel plate capacitor carrying charge q. The induced charge q' on the surface of slab is given by

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Q. A dielectric slab of dielectric constant $K$ is placed between the plates of a parallel plate capacitor carrying charge $q$. The induced charge $q'$ on the surface of slab is given by

Electrostatic Potential and Capacitance

Solution:

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$q'=-q\left(1-\frac{1}{K}\right)$