1. Tardigrade
  2. Question
  3. Chemistry
  4. A dichloroderivative (A) on treating with KCN followed by acid hydrolysis and heating gives a monobasic acid (B) along with liberation of CO2. (B) on heating with liquid ammonia followed by treating with Br2/KOH gives (C) which on treating with NaNO2 and HCl at low temperature followed by oxidation gives a monobasic acid (D) having molecular mass 74. 'C' in the whole process would be

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Q. A dichloroderivative $(A)$ on treating with $KCN$ followed by acid hydrolysis and heating gives a monobasic acid $(B)$ along with liberation of $CO_2$. $(B)$ on heating with liquid ammonia followed by treating with $Br_2/KOH$ gives $(C)$ which on treating with $NaNO_2$ and $HCl$ at low temperature followed by oxidation gives a monobasic acid $(D)$ having molecular mass $74$. $'C'$ in the whole process would be

Amines

Solution:

$- CN$ group on acid hydrolysis always converts to $- COOH$
Two - COOH group on one carbon atom on heating always lose $CO_{2}$ to form mono carboxylic acid. C is propyl amine.
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