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Q.
A dice is thrown twice and the sum of the numbers appearing is observed to be 6. The conditional probability that the number 4 has appeared at least once is:
Probability - Part 2
Solution:
From the given condition sum of a dice thrown twice is 6.
$\therefore $ Number of cases formed is (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5
Since 4 has to occur, and the probability that at least 4 has appeared once is $ = \frac{2}{5}$