Question

A deuteron & an $\alpha $ -particle are placed in an electric field. The forces acting on them are $F_{1}\&F_{2}$ their acceleration are $a_{1}\&a_{2}$ respectively:
(i) $F_{1}=F_{2}$
(ii) $F_{1}\neq F_{2}$
(iii) $a_{1}=a_{2}$
(iv) $a_{1}\neq a_{2}$

• A. (i), (ii)
• B. (ii), (iii)
• C. (ii), (iv)
• D. (i), (iv)

Answer 1

Answer: (B)

Deutron $\left(e , 2 m\right);\alpha $ -particle $\left(2 e , 4 m\right)$
$F_{1}=eE,F_{2}=2eE$
$a_{1}=\frac{e E}{2 m},a_{2}=\frac{2 e E}{4 m}=\frac{e E}{2 m}$
$F_{1}\neq F_{2},a_{1}=a_{2}$