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Q. A Daniel Cell is made at $25^{°}C$ by connecting $Zn/\left(Zn\right)^{+ 2}\left(0 .1 M , 1 litre\right)\&$ $Cu/\left(Cu\right)^{+ 2}\left(\right.0.9M,1litre\left.\right)$ electrode.
The cell is discharged till its emf reaches $1.10$ volt, then it is charged (reversing the discharge process) by passing $0.6F$ charge.
$Given:E_{\frac{Zn}{Zn^{+ 2}}}^{°}=0.76V$
$E_{Cu/Cu^{+ 2}}^{°}=-0.34V,\frac{2 .303 RT}{F}$
$=0.06,log2=0.30\left]\right.$
Select the incorrect option is.

NTA AbhyasNTA Abhyas 2020

Solution:

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