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Q. A cylindrical vessel contains a liquid of density $\rho$ upto a height h. The liquid is closed by a piston of mass m and area of cross section A. There is a small hole at the bottom of the vessel. The speed with which the liquid comes out of the vessel is

Mechanical Properties of Fluids

Solution:

Difference in pressure energy = K.E of the liquid
$\rho gh + \frac{mg}{A} = \frac{1}{2} \rho \nu^2 ; V = \sqrt{2 \left( gh + \frac{mg}{\rho A} \right) }$