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Q. A cylinder of radius $r$ and length $l$ is placed in an uniform electric field in such a way that the axis of the cylinder is parallel to the field. The flux of the field through the cylindrical surface is

Electric Charges and Fields

Solution:

$\Delta \vec{S}$ on cylindrical surface is perpendicular to $\vec{E}$.
$\therefore $ $\Sigma \vec{E} \cdot \Delta \vec{S}=0$