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  4. A cyclist comes to a skidding stop in 10 m. During this process, the force on the cycle due to the road is 200 N and is directly opposite to the motion. How much work does the road do on the cycle?

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Q. A cyclist comes to a skidding stop in $10\, m$. During this process, the force on the cycle due to the road is $200\, N$ and is directly opposite to the motion. How much work does the road do on the cycle?

AP EAMCETAP EAMCET 2020

Solution:

Displacement travelled by cyclist to reach skidding stop, $s=10\, m$
Force on the cyclist due to road,
$F=200\, N$
Since, force is applied directly opposite to motion (or displacement),
hence $\theta=180^{\circ}$
$\therefore $ Work done by the road on the cycle
$W=F s \cos \theta=200 \times 10 \times \cos 180^{\circ}$
$=-2000\, J$