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Q. A current strength of 3.86 amp was passed through molten calcium oxide for 41 minutes and 40 seconds. The mass of calcium in grams deposited at the cathode is (Atomic mass of Ca is 40 g/mol, 1 F = 96500 C)

KEAMKEAM 2012Electrochemistry

Solution:

$I=3.86$ Amp
$t=41\, \min\, 40\, \sec =2500$ seconds
Mass deposited $=Z I t$
$\left[Z=\frac{\text { Equivalent weight }}{96500}\right]$
Equivalent wt. of $C a=\frac{40}{2}=20$
Hence mass deposited
$=\frac{20}{96500} \times 2500 \times 3.86=2\, g$