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  4. A current of strength 2.5 A was passed through CuSO4 solution for 6 minute 265 seconds. The amount of copper deposited is (At. wt. of Cu = 63.5; 1 F = 96500 C)

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Q. A current of strength $2.5\, A$ was passed through $CuSO_{4}$ solution for $6$ minute $265$ seconds. The amount of copper deposited is (At. wt. of $Cu = 63.5; 1 F = 96500 C$)

Electrochemistry

Solution:

$W=ZIt $
$=\frac{E}{96500}\times I\times t $
$=t=6minute+265$ sec
$=360 +265 =625$ sec
$I=2.5A$
$E=\frac{63.5}{2} $
$ W=\frac{63.5}{2\times96500}\times2.5\times625=0.514 g$