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Q. A current of $9.95$ amperes flowing for $10$ minutes, deposits $3\, gm$ of a metal. Equivalent weight of the metal is

AIIMSAIIMS 1997Electrochemistry

Solution:

Charge = Current $\times$ time

$=9.95 \times 10\times 60$

$ 5970 \,C$

$\therefore 5970\,C$ deposites $3\,g$ of metal

$\Rightarrow 96500 \,C$ will deposite $=\frac{3}{5970} \times 96500\, g $ metal

$=48.49\, g$ metal

Therefore equivalent weight is $48.49\, g$