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Q.
A current of 2 A was passed for 1 h through a solution of
$CuSO_{4}. 0.23 7g$ of $Cu^{2+}$ ions was discharged at cathode.
The current efficiency is
Electrochemistry
Solution:
$W=\frac{63.5}{2\times96500}\times60\times60=237\, g$
$\% of efficiency =\frac{0.237}{2.37}\times 100 = 10\%$