Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A current of 2 A was passed for 1 h through a solution of $CuSO_{4}. 0.23 7g$ of $Cu^{2+}$ ions was discharged at cathode. The current efficiency is

Electrochemistry

Solution:

$W=\frac{63.5}{2\times96500}\times60\times60=237\, g$
$\% of efficiency =\frac{0.237}{2.37}\times 100 = 10\%$