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Q. A current of $ 10 \,A $ is passing through a long wire which has semicircular loop of the radius $ 20 \,cm $ as shown in the figure. Magnetic field produced at the centre of the loop isPhysics Question Image

AMUAMU 2019

Solution:

Magnetic field produced at the centre
$B=\frac{1}{2} \left(\frac{\mu_{0}I}{2r}\right)$
According to question,
$I=10\,A$,
$r=20\,cm$
$=20\times10^{-2}\,m$
$=\frac{1}{2}\times\frac{4\pi\times10^{-7}\times10}{2\times20\times10^{-2}}$
$=\frac{\pi\times10^{-6}}{20\times10^{-2}}=5\pi\times10^{-6}T $
$=5\pi\,\mu T$