1. Tardigrade
  2. Question
  3. Chemistry
  4. A current of 0.75 A is passed through an acidic solution of CuSO4 for 10 minutes. The volume of oxygen liberated at anode (at STP) will be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A current of $0.75$ A is passed through an acidic solution of $CuSO_{4}$ for 10 minutes. The volume of oxygen liberated at anode (at STP) will be

Electrochemistry

Solution:

$2O^{2-} \to O_{2} +4e$
Mole of e$ =\frac{0.75\times10\times60}{96500}$
Mole of $O_{2}=\frac{4.66\times10^{-3}}{4}=0.0261 L$