Question

A current is passed through two cells connected in series. The first cell contains $X \, (NO_3)$$_{3(aq)}$ and the second cell contains $Y \, (NO_3)$$_{2(aq)}$. The relative atomic mases of X and Y are in the ratio $1 : 2$. What is the ratio of liberated mass of $X$ to that of $Y$ ?

• A. 3 : 2
• B. 1 : 2
• C. 1 : 3
• D. 3 : 1
• E. 2 : 1

Answer 1

Answer: (C)

If atomic mass of $X = a$, then that of $Y = 2\, a.$
As eq. wt = atomic mass/valency
Eq. wt. of $ X = a/3$, Eq. wt. of $Y = 2 a/2 = a.$
$ \frac{\text{Mass of }\, X}{\text{Mass of} \, Y} = \frac{\text{Eq.wt, of } \, X}{\text{Eq.wt, of } \, Y} = \frac{a/3}{a} = \frac{1}{3} = 1:3.$