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Q. A current-carrying straight wire is kept along the axis of a circular loop carrying a current. The straight wire

NTA AbhyasNTA Abhyas 2022

Solution:

According to Fleming's left hand rule, direction of magnetic field at the centre $O.$
The force on the current carrying conductor is $F=i\overset{ \rightarrow }{d l}\times \, \overset{ \rightarrow }{B}$
Solution
As angle between $dl$ and B is zero
$ \, F=0$
The straight wire will not exert any force on the circular loop.