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  4. A current carrying rectangular loop P Q R S is made of uniform wire. The length P R=Q S=5 cm and P Q=R S=100 cm. If ammeter current reading changes from I to 2 I, the ratio of magnetic forces per unit length on the wire P Q due to wire R S in the two cases respectively (fP QI: fP Q2 I) is:

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Q. A current carrying rectangular loop $P Q R S$ is made of uniform wire. The length $P R=Q S=5 \,cm$ and $P Q=R S=100\, cm$. If ammeter current reading changes from $I$ to $2 I$, the ratio of magnetic forces per unit length on the wire $P Q$ due to wire $R S$ in the two cases respectively $\left(f_{P Q}^I: f_{P Q}^{2 I}\right)$ is:Physics Question Image

JEE MainJEE Main 2023Moving Charges and Magnetism

Solution:

$F \propto I _1 I _2$
$F _1: F _{2 I }=1: 4$