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  4. A current carrying conductor is bent into a quarter of a circle of radius R as shown. The magnetic field at the centre O is

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Q. A current carrying conductor is bent into a quarter of a circle of radius $R$ as shown. The magnetic field at the centre $O$ isPhysics Question Image

COMEDKCOMEDK 2007Moving Charges and Magnetism

Solution:

Magnetic field due to straight parts at the point O will be zero as the current elements and the position vectors at that point are parallel. Magnetic field due to circular arc is given by,
$\overline{B_{0}} = \frac{\mu_{0} I}{4 \pi R} \left(\frac{\pi}{2}\right) \otimes = \frac{\mu_{0} I}{8R} \otimes $

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