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Q. A cubical copper block has each side $2.0\, cm$. It is suspended by a string and submerged in oil of density $820\, kg / m ^{3}$. The tension in the string is (density of copper $8920\, kg / m ^{3}, g=10\, m / s ^{2}$ )

ManipalManipal 2011

Solution:

Tension, $T=m g-$ buoyant force
$=V \rho g-V \sigma g=V(\rho-\sigma) g=l^{3}(\rho-\sigma) g$
$=8 \times 10^{-6}(8920-820) \times 10$
$=0.648\, N$