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Q. A cubical block of mass $M$ and edge a slides down a rough inclined plane of inclination $\theta$ with a uniform velocity. The torque of the normal force on the block about its centre has a magnitude

Solution:

$\tau_{N}=\tau_{f}$
$\tau_{N}=f \cdot \frac{a}{2}=m g \sin \theta \frac{a}{2}$
$\tau_{N}=\frac{1}{2} m g\, a\, \sin \theta$