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Q. A cube has a side of length $1.2\times 10^{-2}m$. Its volume up to correct significant figures is

Physical World, Units and Measurements

Solution:

Here
Length of the cube, $L = 1.2 \times 10^{-2} m$
Volume of the cube, $V=\left(1.2\times10^{-2}m\right)^{3}$
$= 1.728 \times 10^{-6}m^{3}$
As the result can have only two significant figures
therefore, on rounding off, we get
$V=1.7 \times 10^{-6}m^{3}$