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Q.
A Cu disc of radius 0.1 m rotates about its centre with 10 rps in a uniform magnetic field of 0.1 T. The emf induced across the radius of the disc is
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Solution:
The induced emf between centre and rim of the rotating disc $ E=\frac{1}{2}B\omega {{R}^{2}} $ $ =\frac{1}{2}\times 0.1\times 2\pi \times 10\times {{(0.1)}^{2}} $ $ =10\pi \times {{10}^{-3}}V $ $ =10\pi \,mV $