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Q. A cricket player catches a ball of mass 0.1 kg moving with a speed of $10\,ms^{-1}$ in 0.1 second. Force exerted by him is (in N)

KCETKCET 1999Laws of Motion

Solution:

Here $ F \times t = m \upsilon$
i.e. F = $\frac{m \upsilon }{t} = \frac{0.1 \times 10}{0.1} $
$= 10\, N$