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Q. A cricket ball of mass $250\, g$ collides with a bat with velocity $10 \,m/s$ and returns with the same velocity within $0.01$ second. The force acted on bat is

Laws of Motion

Solution:

Force $=m \left(\frac{dv}{dt}\right)$
$=\frac{0.25 \times [(10)-(-10)]}{0.01}$
$=25 \times 20 =500 \,N$