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Q. A cricket ball of mass $160 \,g$ is moving horizontally directly towards a batsman. Its speed just before it hits the bat is $30\, m / s$. It leaves the bat at $40 \,m / s$ at $90^{\circ}$ to its original direction. Find the magnitude of the impulse (in N-s) imparted to the ball.

Laws of Motion

Solution:

| Impulse $\mid=$
$\Delta P = m |\Delta \vec{ v }|$
$=\frac{160}{1000} \sqrt{\left[(30)^{2}+(40)^{2}\right]}=8\, Ns$