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  4. A copper block of mass 50 g is heated to 100° C and placed on a block of ice at 0° C. The specific heat of copper is 0.1 cal g -1 ° C -1 and latent heat of ice is 80 cal g -1 . The amount of ice melted is

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Q. A copper block of mass 50 g is heated to $100^{\circ} C$ and placed on a block of ice at $0^{\circ} C$. The specific heat of copper is 0.1 cal $g ^{-1}{ }^{\circ} C ^{-1}$ and latent heat of ice is 80 cal $g ^{-1} .$ The amount of ice melted is

Thermal Properties of Matter

Solution:

Heat lost by copper = Heat gained by ice
$(50 g )\left(0.1\right.$ cal $\left. g ^{-1} C ^{-1}\right)(100-0)^{\circ} C =(\Delta m) \cdot 80$
$\Rightarrow \Delta m=\frac{50 \times 0.1 \times 100}{80}=6.25 \,g$