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Q. A copper block of mass $2.5\, kg$ is heated in a furnace to a temperature of $500^{\circ} C$ and then placed on large ice block. The maximum amount (in $kg$ ) of ice that can melt is (Specific heat of copper $=0.39\, Jg ^{-1} {}^{\circ}C ^{-1}$, latent heat of fusion of water $=335\, Jg ^{-1}$ )

Thermal Properties of Matter

Solution:

$m_{I}L _{f}= m _{ c } S _{ c } \Delta T _{ c }$
$\Rightarrow m _{ I }=\frac{ m _{ c } S _{ C } \Delta T _{ C }}{ L _{ f }}$
$=\frac{2.5 \times 0.39 \times(500-0)}{335}$
$=1.455\, Kg$