The surface area of the ball
$A=4 \pi r^{2}=(4 \pi)(0.02 m )^{2}=0.005\, m ^{2}$
and its absolute temperature is
$T =327+273=600\, K . $ Hence
$P =e \sigma AT ^{4} $
$=\left(0.3 \times 5.67 \times 10^{-8} \times 0.005 \times(600)^{4}\right.$
$=11.0 \,W$