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Q. A conveyor belt is moving horizontally at a speed of $4 ms^{-1}$. A box of mass 20 kg is gently laid on it. It takes 0.1 s for the box to come to rest. If the belt continues to move uniformly, then the distance moved by the box on the conveyor belt is

Motion in a Straight Line

Solution:

From first equation of motion
v = u + at
0 = -4 + a $\times (0.1)$
$\Rightarrow $ a=40 $4ms^{-2}$
$s=\frac{v^2}{2a}$
$\Rightarrow s=\frac{(4)^2}{2 \times 40}$
$\Rightarrow s=\frac{16}{80} \Rightarrow s=0.2 m$