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  4. A conveyor belt is moving at a constant speed of 2 m s -1. A box is gently dropped on it. The coefficient of friction between them is μ=0.5. The distance that the box will move relative to belt before coming to rest on it taking g=10 ms -2, is

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Q. A conveyor belt is moving at a constant speed of $2\, m s ^{-1}$. A box is gently dropped on it. The coefficient of friction between them is $\mu=0.5$. The distance that the box will move relative to belt before coming to rest on it taking $g=10\, ms ^{-2}$, is

NTA AbhyasNTA Abhyas 2022

Solution:

The frictional force on the box $f=\mu\, m g$
$\therefore$ Acceleration in the box
$a=\mu g=5\, m s^{-2}$
$v^{2}=u^{2}+2 a s$
$4=0+2 \times 5 \times s$
$s=0.4 \,m$