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Physics
A converging lens has a focal length of 50 cm The power of the lens is:
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Q. A converging lens has a focal length of 50 cm The power of the lens is:
KEAM
KEAM 2000
A
$ +5D $
B
$ +2D $
C
$ +0.5D $
D
$ -0.5D $
E
$ -2D $
Solution:
Power of a lens is inverse of focal length (in metres) $ P=\frac{1}{f} $ Given, $ f=50\text{ }cm $ $ \therefore $ $ P=\frac{100}{50}=+2D $