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Q. A container with square base of side a is filled up to a height $H$ with a liquid. A hole is made at a depth $h$ from the free surface of water. With what acceleration the container must be accelerated, so that the water does not come out?

J & K CETJ & K CET 2005

Solution:

Bernoulli's theorem is a form of conservation of energy, hence we have
$ H_{0}+h\,\rho g=H_{0}+\frac{1}{2}\rho V^{2} $
When vessel is accelerated down with an acceleration $g$ (free fall), then pseudo acceleration $g$ will act vertically upwards and effective value of $g$ is zero.
Hence, water will not flow.

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