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Q. A constant torque acting on a uniform circular wheel changes its angular momentum from $A _{0}$ to $4 A _{0}$ in $4 \,s$. The magnitude of this torque is

Chhattisgarh PMTChhattisgarh PMT 2007

Solution:

Change in angular momentum
$=4 A_{0}-A_{0}$
$\Delta L=3 A_{0}$
Torque, $\tau=\frac{\Delta L}{\Delta t}$
$\tau=\frac{3 A_{0}}{4}$