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  4. A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms -1. The time the body takes to stop is

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Q. A constant retarding force of $50\, N$ is applied to a body of mass $20\, kg$ moving initially with a speed of $15 \,ms ^{-1}$. The time the body takes to stop is

Laws of Motion

Solution:

$a=\frac{F}{M}=\frac{50 N }{20 kg }=2.5 m / s ^{2} \Rightarrow t=\frac{v-u}{a}$
$=\left(\frac{0-15}{-2.5}\right) s =6 \,s$