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Q. A constant pressure air thermometer gave a reading of 47.5 units of volume when immersed in ice cold water, and 67 units in a boiling liquid. The boiling point of the liquid will be

Rajasthan PMTRajasthan PMT 2010

Solution:

Initial volume $ ~{{V}_{1}}=47.5\,\,unit $ Temperature of ice cold water $ {{T}_{1}}={{0}^{o}}C=273\,\,K $ Final volume of $ {{V}_{2}}=67\,\,unit $ Applying Charles law, we have $ \frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}} $ (where temperature $ {{T}_{2}} $ is the boiling point) or $ {{T}_{2}}=\frac{{{V}_{2}}}{{{V}_{1}}}\times {{T}_{1}}=\frac{67\times 273}{47.5} $ $ =385K={{112}^{o}}C $