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Q.
A constant force acts on a body of mass $0.9\, kg$ at rest for $10 \,s$. If the body moves a distance of $250 \,m$ the magnitude of the force is:
EAMCETEAMCET 2000
Solution:
By using the equation
$S = ut +\frac{1}{2} a t ^{2}$
As the initial velocity is zero
By substituting the values we get
$250=50 a$
The acceleration is $5 \frac{ m }{ \sec ^{2}}$
We know that
$F = m \times a$
We get
$F =0.9 \times 5$
Hence the force is $4.5 \,N$