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Q. A cone of base radius R and height h is located in a uniform electric field $\overrightarrow{E}$ parallel to its base. The electric flux entering the cone is :

JEE MainJEE Main 2014Electric Charges and Fields

Solution:

flux $\phi = E\cdot A_{\bot}$
$= E\left(\frac{1}{2}h\times2R\right)$
$= Ehr$

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