Question

A conductor with a cavity is charged positively and its surface charge density of$\sigma$ . If E and $V$ represent the electric field and potential, then inside the cavity

• A. $ \sigma$ = 0 and V = 0
• B. E= 0 and V= 0
• C. E = 0 and $ \sigma $ = constant
• D. V= 0 and V= 0 and $ \sigma $= constant = constant
• E. E= 0 and V= constant

Answer 1

Answer: (E)

Surface charge density $=\sigma$
Inside the surface, the electric field is zero.
$\Rightarrow E_{\text {inside }}=0$
$\because V_{\text {inside }}=V_{\text {surface }}$
The potential inside the surface of charged sphere is constant
$\therefore E=0, V=$ constant