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Q.
A conductor wire having $10^{29}$ free electrons $/ m ^{3}$ carries a current of $20 \,A$. If The cross section of the wire is $1\, mm ^{2}$ then the drift velocity of electrons will be $\left(e=1.6 \times 10^{-19} C \right)$
Solution:
$i=n e A V_{d}$
$20=10^{29} \times 1.6 \times 10^{-19} \times 10^{-6} \times V_{d}$
$V_{d}=1.25 \times 10^{-3} m / s$