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Physics
A conductor has 14.4× 10-19C positive charge. The conductor has :
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Q. A conductor has $ 14.4\times {{10}^{-19}}C $ positive charge. The conductor has :
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A
excess of 27 electrons
B
excess of 9 electrons
C
short of 27 electrons
D
short of 9 electrons
Solution:
$ q=ne $ $ 14.4\times {{10}^{-19}}=n\times 1.6\times {{10}^{-19}} $ $ n=9 $ Conductor has positive charge, it means it has short of 9 electrons.