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Q. A conducting sphere of radius $5\, cm$ has an unknown charge. The electric field at $10\, cm$ from the centre of the sphere is $1.8 \times 10^{3} N / C$ and points radially inward. What is the net charge on the sphere?

J & K CETJ & K CET 2014Electric Charges and Fields

Solution:

For a conducting charged sphere, the electric field outside the sphere
$(E)=\frac{1}{4 \pi \varepsilon_{0}} \frac{Q}{r^{2}}$
$1.8 \times 10^{3}=9 \times 10^{9} \times \frac{Q}{(0.1)^{2}}$
$Q=\frac{1.8 \times 10^{3} \times 10^{-2}}{9 \times 10^{9}}$
$=2 \times 10^{-9} C $
$=2 \,n C$