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Q. A conducting ring of radius $r$ is rolling without slipping with a constant angular velocity $\omega $ (figure). If the magnetic field strength is $B$ and is directed into the page then the emf induced across $PQ$ isPhysics Question Image

Electromagnetic Induction

Solution:

$|E| =$ Magnitude of induced emf
$= \frac{Bl^2}{2} \omega, l = \sqrt{2} r$
$E = \frac{B(2r^2) \omega}{2} = B \omega r^2$